leetcode 数字翻转

public int reverse(int x) {
        int result = 0;
        while (x != 0) {
            int temp = x % 10;
            if (result > Integer.MAX_VALUE / 10 || (result == Integer.MAX_VALUE / 10 && temp % 10 > 7)) {
                return 0;
            }
            if (result < Integer.MIN_VALUE / 10 || (result == Integer.MIN_VALUE / 10 && temp % 10 < -8)) {
                return 0;
            }
            result = result * 10 + temp;
            x = x / 10;
        }
        return result;
    }